I am available for work right now, if you are interested then email me directly.
Following on from my last post on axes positioning, I have added the functionality to add a tangent to the curve on mousemove
. You can see a working example here by dragging the mouse over the svg document.
Below is a screenshot of the end result:
The first steps are to create the elements that I will use to display the tangent indicator and also to hook up an event listener for mousemove
on the svg document:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 

The above creates a circle to indicate where on the curve the mouse is relative to the x axis. A label is created to display the coordinate that the mouse is currently on with respect to the curve and lastly I create a line that will display the tangent.
Line 19 adds a mousemove
handler to the svg
element that has been previously created with the code below:
1 2 3 4 5 6 7 8 9 10 

The goal of the mousemove
handler is to draw the tangent of the curve with respect to the x axis as the mouse moves over the svg document.
In geometry, the tangent line to a plane curve at a given point is the straight line that just touches the curve at that point.
I can get the x
for the tangent line from the mouse coordinates of the mousemove
function:
1 2 3 4 

With this, I can use mathematical differential calculus to work out the tangent line. If I was to perform these steps with pen and paper, I would take the following steps:
 Find the derivative of the curve
 Substitute the
x
retreived from themousemove
event into the derivative to calculate the gradient (or slope for the US listeners) of the line.  Substitute the gradient of the tangent and the coordinates of the given point into the equation of the line in the format
y = mx + c
.  Solve the equation of the line for y.
What was surprising and enjoyable for me was that the steps on paper transferred into machine instructions quite well which is not always the case.
Before I plot the line, I want to position my circle and label onto the curve. I am already using the excellent mathjs library to get the coordinates to draw the curve:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 

Line 2 of the above code uses mathjs
’s parse function to create an expression from the string input of the form:
Once I have the expression, I can evaluate it with different values. Lines 5 and line 9 evaluates the expression for each x
value in a predetermined range of values. Line 19 plots the line.
As I know what x
is from the mouse event, I can use mathjs to parse my expression with respect to x and get the y
coordinate to position my label on the curve:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 

Lines 2 and 4 retrive x
from the mouse event and line 6 evaluates y
by parsing and evaluating the equation of the curve with respect to x. I then use the x
and y
coordinates to position my label elements.
Mathjs does not come with its own differentiation module to work out the derivative of the user entered expression but I found this plugin that seems to work out well for this task.
Armed with this module, it was plain sailing to create an equation for the tangent line that I could use to find out y
values for the tangent.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 

 Line 1 creates a derivative function from the equation of the curve.
 The derivative function is evaluted to get the gradient or slope for the US viewers on line 3.
 The
c
constant or yintercept of the equation of the liney = mx + c
is retrieved on line 5.  Mathjs is employed to create an expression in the format of
y = mx + c
.  A
getTangentPoint
function is created that will be used to get the points at either end of the function.  Lines 24  26 create 2 points for
x
that will be far off the length and height of the svg document to give the impression of stretching off to infinity.  Each point gets its
y
value by calling thegetTangentPoint
funtion on line 9 that in turn will solve forx
for the equation of the line function previously created on line 7.  Once we have the pair of points, the line can be plotted on lines 29  33.
You can see the end result here.
The following util function will return the yintercept for a point and gradient:
1 2 3 

I am available for work right now, if you are interested then email me directly.